Seahawkfan80":dx808ddf said:
Silver Hawk":dx808ddf said:
sdog1981":dx808ddf said:
8 win Washington is in over 8 win Seahawks due to win percentage in common games. I don't think I've seen that one before.
If it came down to the 8-8 scenario, the Seahawks and Redskins would tie on conference record. They would also tie on common games. So, the next tie break would be strength of victory, which would be a bit of a crap shoot.
As far as common games, each team would have 4-1 records. The common games include AZ, GB, Carolina and Dallas. You have 5 games each since Seattle plays AZ twice and Washington plays Dallas twice.
Ok...this is a little muddy for me. I do understand that Washington plays Dallas 2 times, we play them one time. I understand that we play Az 2x and Washington played them one time. So How do we get to the common games that they use both dallas games and we use both Az games? I would think that we would use a win as a barometer as it is based on wins. If they end up 1-1 in the division, the win takes precedence. If they go 0-2 or 2-0, then wins dont really matter with exception of the amount of wins. One game is common opponents, is it not? We did not play Dallas 2 times, only one? UW only played Az one time, not twice. I looked at the site and it did not specify. I also looked for how they would determine this more by scores and there was a distinct method.
https://www.nfl.com/standings/tiebreakingprocedures
Please advise.
Yes - you just tally up the total wins and losses (and ties) related to the common opponents and calculate the win percentage. This (using the win percentage) is because one team may have played more games against common opponents due to a common opponent being in the same division as one of the teams. For example, as you note, AZ is a common opponent but we played them twice. We count them twice, Washington counts them once. They count Dallas twice, we count Dallas once.
For the site you mention, scroll down to the “Other Tie-Breaking Procedures” section. Item 2 says: “In comparing records against common opponents among tied teams, the best won-lost-tied percentage is the deciding factor, since teams may have played an unequal number of games”.